(+n^2-4n-3n+12)(n-5)=210

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Solution for (+n^2-4n-3n+12)(n-5)=210 equation:



(+n^2-4n-3n+12)(n-5)=210
We move all terms to the left:
(+n^2-4n-3n+12)(n-5)-(210)=0
We move all terms containing n to the left, all other terms to the right
(+n^2-4n-3n+12)(n-5)=210

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